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HRID424750

反应详情

EQUATION

反应方程式

HRID 424750 的结构方程式

REACTANTS

反应物

2
结构：O=C(O)c1cn(C2CC2)c2cc(F)c(F)cc2c1=O
HCID5210422

1-Cyclopropyl-6,7-difluoro-4-oxo-1,4-dihydroquinoline-3-carboxylic acid

C13H9F2NO3

结构：F[C@@H]1CNC[C@@H]1CNC1CC1
HCID11147857

未命名化合物

PRODUCTS

生成物

1
结构：O=C(O)c1cn(C2CC2)c2cc(N3C[C@H](CNC4CC4)[C@H](F)C3)c(F)cc2c1=O
HCID66704977

未命名化合物

收率 48.9%

PROCEDURE

实验过程

Using 1-cyclopropyl-6,7-difluoro-1,4-dihydro-4-oxo-3-quinolinecarboxylic acid (199 mg) and (3R,4S)-3-cyclopropylaminomethyl-4-fluoropyrrolidine (131 mg), the same procedure was followed as in Example 23 to give 1-cyclopropyl-7-[(3S,4S)-3-cyclopropylaminomethyl-4-fluoro-1-pyrrolidinyl]-6-fluoro-1,4-dihydro-4-oxo-3-quinolinecarboxylic acid as pale yellow crystals (148 mg).