HRID42601

反应详情

EQUATION

反应方程式

HRID 42601 的结构方程式

PROCEDURE

实验过程

Following a similar procedure to that described in examples 6 and 7, but using 4,6-diphenyl-5-(4-pyridyl)-1H-pyrazolo[3,4-b]pyridine (obtained in example 2) instead of 4,6-bis(4-fluorophenyl)-5-(4-pyridyl)-1H-pyrazolo[3,4-b]pyridine and N-(2-bromoethyl)phthalimide instead of iodoethane, the title compound was obtained (yield: 31%).