3-Fluoroaniline → 219492-65-6
Reaction equation
[F:1][C:2]1[CH:3]=[C:4]([CH:6]=[CH:7][CH:8]=1)[NH2:5].[N+:9]([C:12]1[CH:20]=[CH:19][CH:18]=[CH:17][C:13]=1[C:14](Cl)=[O:15])([O-:11])=[O:10]>>[N+:9]([C:12]1[CH:20]=[CH:19][CH:18]=[CH:17][C:13]=1[C:14]([NH:5][C:4]1[CH:6]=[CH:7][CH:8]=[C:2]([F:1])[CH:3]=1)=[O:15])([O-:11])=[O:10]Participants
3
Procedure
Using the procedure described in Example 93, Part A, 3-fluoroaniline (15.6 mmol) and 2-nitrobenzoyl chloride (17.2 mmol) yielded 3.09 g (76%) of the title compound.
Sources & evidence
- ORD record
- ord-c7134a2b05e64c19b7fabcd5f788ae4f
- Source dataset
- uspto-grants-2001_11
- Patent number
- US06313122B1
Reaction notes
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