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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 428652Generated: October 28, 2026

Water → HCID 9867927, compound

https://huagongshe.com/reaction/428652

Reaction equation

Participants

RoleNameHCIDCharge
ReactantWaterHCID 962—
ReactantHCID 14894694HCID 14894694—
Reactant(Z)-1,3-dihydro-4-iodo-3-[(1H-pyrrol-2-yl)methylene]-indol-2-oneHCID 15548052—
CatalystCopper(1+) iodide; Copper(I) iodide; Cuprous iodide; Cuprous iodide (CuI)HCID 24350—
CatalystTetrakis(triphenylphosphine)palladiumHCID 11979704—
SolventTetrahydrofuranHCID 8028—
SolventTriethylamineHCID 8471—
ProductHCID 9867927HCID 9867927—

Reaction Steps

A solution of (Z)-1,3-dihydro-4-iodo-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one (from Example 71, infra) (50 mg, 0.15 mmol), and 5-(2-propynyl)-6(5H)-phenanthridinone (45 mg, 0.19 mmol) (prepared according to Walser et al., J. Med. Chem. 34(3), 1209-1221 (1991)) in 1 mL tetrahydrofuran and 1 mL triethylamine was degassed by bubbling argon through the solution for 10 minutes. At this time, copper (I) iodide (11 mg, 0.06 mmol) and tetrakis(triphenylphosphine) palladium(0) (3 mg, 0.03 mmol) were added, and the reaction was stirred at room temperature for 72 hours. Water (10 mL) was then added and the precipitate was filtered off and dried. The product was purified via flash column chromatography (SiO2, 230-400 mesh) with ethyl acetate/hexane, to yield a yellow powder which was recrystallized from ethyl acetate/hexane, to give (Z)-5-[3-[2,3-dihydro-2-oxo-3-(1H-pyrrol-2-ylmethylene)-1H-indol-4-yl]-2-propynyl]-6(5H)-phenanthridinone. (Yield 25 mg, 38%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06313310B1
Source datasetuspto-grants-2001_11
ORD IDord-1479dba332be46fe848067d6b4cda794
Source noteuspto-grants-2001_11