Methanol → Methyl 3-methyl-6-(phenylthio)-benzoate
Reaction equation
[CH3:1][C:2]1[CH:3]=[C:4]([C:8]([S:11][C:12]2[CH:17]=[CH:16][CH:15]=[CH:14][CH:13]=2)=[CH:9][CH:10]=1)[C:5]([OH:7])=[O:6].S(=O)(=O)(O)O.[CH3:23]O>>[CH3:1][C:2]1[CH:3]=[C:4]([C:8]([S:11][C:12]2[CH:17]=[CH:16][CH:15]=[CH:14][CH:13]=2)=[CH:9][CH:10]=1)[C:5]([O:7][CH3:23])=[O:6]Participants
4
Procedure
650 g of 3-methyl-6-(phenylthio)-benzoic acid in 7.5 litres of absolute methanol are slowly treated with 300 ml of concentrated sulphuric acid and the mixture is heated for 24 hours under reflux. The mixture is concentrated and the residue poured on to an ice-cold sodium bicarbonate solution. The mass is extracted with ether, washed with water, dried over sodium sulphate and concentrated. There is obtained methyl 3-methyl-6-(phenylthio)-benzoate as a red-brown oil which crystallises on standing.
Workup
- temperaturethe mixture is heated for 24 hours
- temperatureunder reflux
- concentrationThe mixture is concentrated
- additionthe residue poured on to an ice-cold sodium bicarbonate solution
- extractionThe mass is extracted with ether
- washwashed with water
- dry with materialdried over sodium sulphate
- concentrationconcentrated
Sources & evidence
- ORD record
- ord-4688c237d58743a7af3a3ee3fdad7b57
- Source dataset
- uspto-grants-1977_02
- Patent number
- US04006145
Reaction notes
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