Thiophenol → 5-Fluoro-2-(phenylthio)benzoic acid
Reaction equation
[OH-].[K+].[C:3]1([SH:9])[CH:8]=[CH:7][CH:6]=[CH:5][CH:4]=1.[F:10][C:11]1[CH:12]=[CH:13][C:14](I)=[C:15]([CH:19]=1)[C:16]([OH:18])=[O:17]>O.[Cu]>[F:10][C:11]1[CH:19]=[C:15]([C:14]([S:9][C:3]2[CH:8]=[CH:7][CH:6]=[CH:5][CH:4]=2)=[CH:13][CH:12]=1)[C:16]([OH:18])=[O:17]Participants
6
Reactant 3
Product 1
Reagents, catalysts & solvents 2
Procedure
A solution of 150 g of potassium hydroxide in 850 ml of water is treated with 47.5 ml of thiophenol at 55° C under a nitrogen atmosphere. The mixture is stirred for 15 minutes and subsequently treated with 1.9 g of copper powder and 207 g of 5-fluoro-2-iodo-benzoic acid. The mixture is heated under reflux for 7 hours, filtered while hot, cooled and acidified with concentrated hydrochloric acid. The precipitated product is filtered off, washed with water and dried. There is obtained 3-fluoro-6-(phenylthio)-benzoic acid which melts at 146°-148° C.
Workup
- temperatureThe mixture is heated
- temperatureunder reflux for 7 hours
- filtrationfiltered while hot,
- temperaturecooled
- filtrationThe precipitated product is filtered off
- washwashed with water
- customdried
Sources & evidence
- ORD record
- ord-af96e67ea7bb4697abcd0be9e4193382
- Source dataset
- uspto-grants-1977_02
- Patent number
- US04006144
Reaction notes
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