Sodium Nitrate → HCID 21429343, compound

HRID 437609Notes

Reaction equation

HRID 437609 reaction equation
[N+:1]([O-:4])([O-])=[O:2].[Na+].[F:6][C:7]1[CH:12]=[C:11]([I:13])[CH:10]=[C:9](I)[C:8]=1[OH:15]>C(O)(=O)C>[F:6][C:7]1[CH:12]=[C:11]([I:13])[CH:10]=[C:9]([N+:1]([O-:4])=[O:2])[C:8]=1[OH:15]

Participants

4

Reactant 2

HCID 24268Sodium NitrateHCID 23270180HCID 23270180, compound

Product 1

HCID 21429343HCID 21429343, compound

Reagents, catalysts & solvents 1

HCID 176Acetic AcidSolvent

Procedure

Sodium nitrate (4.3 g) was added in portions over 1 hour to a solution of 2-fluoro-4,6-diiodophenol (16.3 g) in acetic acid (100 ml). The mixture was stirred for a further 15 minutes and was then poured into ice water (250 ml). The aqueous solution was concentrated under reduced pressure, extracted with chloroform and the organic solvent removed under reduced pressure. The residue was steam distilled to give 2-fluoro-4-iodo-6-nitrophenol which crystallised from aqueous ethanol (1.8 g) m.p. 96°.

Workup

  1. concentrationThe aqueous solution was concentrated under reduced pressure
  2. extractionextracted with chloroform
  3. customthe organic solvent removed under reduced pressure
  4. distillationdistilled

Sources & evidence

ORD record
ord-4a81c2b3e1e9496391fec9938bb27ddf
Source dataset
uspto-grants-1977_06
Patent number
US04031249

Reaction notes

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