Iodide Ion → 3,5-Heptanedione
Reaction equation
ClC1C=C(OC)C=CC=1OCCOCC[CH:10]([C:15](=[O:18])[CH2:16][CH3:17])[C:11](=[O:14])[CH2:12][CH3:13].[I-].[Li]>>[CH3:17][CH2:16][C:15](=[O:18])[CH2:10][C:11](=[O:14])[CH2:12][CH3:13]Participants
4
Procedure
4{2-[2-(2-Chloro-4-methoxyphenoxy)ethoxy]ethyl}-3,5-heptane-dione [I; Ar is 2-Cl-4-CH3OC6H3, Alk is (CH2)2O(CH2)2, R and R' are CH3CH2CO] was prepared from 65.1 g. of the iodide from part (b) and the lithium salt derived from 41.0 g. of 3,5-heptanedione to give 12.1 g. of product, b.p. 168°-172° C. (0.005 mm.).
Workup
- customwas prepared from 65.1 g
Sources & evidence
- ORD record
- ord-14eb05cf19d045cea1545ed4c20a9bcb
- Source dataset
- uspto-grants-1977_06
- Patent number
- US04031246
Reaction notes
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