HRID437690

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID10868

Dicyclohexylcarbodiimide

C13H22N2

3 次

结构：CC(C)(C)OC(=O)N[C@@H](Cc1c[nH]c2ccccc12)C(=O)O

HCID83169

L-Tryptophan, N-[(1,1-dimethylethoxy)carbonyl]-

C16H20N2O4

结构：CC(C)(C)OC(=O)N[C@@H](COCc1ccccc1)C(=O)O

HCID90234

L-Serine, N-[(1,1-dimethylethoxy)carbonyl]-O-(phenylmethyl)-

C15H21NO5

HCID637606

Boc-D-alanine

C8H15NO4

结构：CC(C)(C)OC(=O)N[C@H](Cc1ccc(OCc2ccccc2)cc1)C(=O)O

HCID6992575

未命名化合物

PRODUCTS

生成物

结构：COC(=O)[C@@H](C)NC(=O)[C@@H](Cc1ccc(OCc2ccccc2)cc1)NC(=O)[C@H](COCc1ccccc1)NC(=O)[C@H](Cc1c[nH]c2ccccc12)NC(=O)OC(C)(C)C

HCID54340573

未命名化合物

PROCEDURE

实验过程

Nα-t-Butoxycarbonyl-L-tryptophyl-O-benzyl-L-seryl-O-benzyl-D-tyrosyl-D-alanine resin is obtained according to the procedure of Example 1 by treating 20 g. of Nα-t-butoxycarbonyl-D-alanine resin, 0.0132 mol, with 7.4 g., 0.02 mol, of Nα-t-butoxycarbonyl-O-benzyl-D-tyrosine and 4.1 g., 0.02 mol, of dicyclohexylcarbodiimide, (2) 6.0 g., 0.02 mol, of Nα-t-butoxycarbonyl-O-benzyl-L-serine and 4.1 g. of dicyclohexylcarbodiimide, and (3) 6.1 g. of Nα-t-butoxycarbonyl-L-tryptophan and 4.1 g. of dicyclohexylcarbodiimide.

WORKUP

后处理

additionby treating 20 g

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-a241e9b4db8e44bd8139d5072b78c7cf
来源数据集: uspto-grants-1977_06
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04031069
来源说明: uspto-grants-1977_06

反应 SMILES

C(OC([NH:8][C@@H:9]([C:11]([OH:13])=[O:12])[CH3:10])=O)(C)(C)C.C(O[C:19]([NH:21][C@@H:22]([C:38]([OH:40])=O)[CH2:23][C:24]1[CH:29]=[CH:28][C:27]([O:30][CH2:31][C:32]2[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=2)=[CH:26][CH:25]=1)=[O:20])(C)(C)C.[CH:41]1(N=C=NC2CCCCC2)CCCCC1.C(O[C:61]([NH:63][C@H:64](C(O)=O)[CH2:65][O:66][CH2:67][C:68]1[CH:73]=[CH:72][CH:71]=[CH:70][CH:69]=1)=[O:62])(C)(C)C.[C:77]([O:81][C:82]([NH:84][C@H:85](C(O)=O)[CH2:86][C:87]1[C:95]2[C:90](=[CH:91][CH:92]=[CH:93][CH:94]=2)[NH:89][CH:88]=1)=[O:83])([CH3:80])([CH3:79])[CH3:78]>>[CH3:41][O:13][C:11](=[O:12])[C@@H:9]([CH3:10])[NH:8][C:38](=[O:40])[C@@H:22]([CH2:23][C:24]1[CH:25]=[CH:26][C:27]([O:30][CH2:31][C:32]2[CH:33]=[CH:34][CH:35]=[CH:36][CH:37]=2)=[CH:28][CH:29]=1)[NH:21][C:19](=[O:20])[C@H:64]([CH2:65][O:66][CH2:67][C:68]1[CH:69]=[CH:70][CH:71]=[CH:72][CH:73]=1)[NH:63][C:61](=[O:62])[C@H:85]([CH2:86][C:87]1[C:95]2[C:90](=[CH:91][CH:92]=[CH:93][CH:94]=2)[NH:89][CH:88]=1)[NH:84][C:82]([O:81][C:77]([CH3:78])([CH3:79])[CH3:80])=[O:83]