p-Chlorothiophenol → Bis(p-chlorophenyl)disulfide
Reaction equation
[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([SH:8])=[CH:4][CH:3]=1>N1C=CC=CC=1>[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([S:8][S:8][C:5]2[CH:6]=[CH:7][C:2]([Cl:1])=[CH:3][CH:4]=2)=[CH:4][CH:3]=1Participants
3
Reactant 1
Product 1
Reagents, catalysts & solvents 1
Procedure
To a solution of 1.4 g. of p-chlorobenzenethiol in 5 ml. pyridine, 960 mg. of methyl xanthide was added in one portion. Evaporation of excess pyridine and volatile byproduct gave the known bis(p-chlorophenyl) disulfide in quantitative yield (1.4 g.). No free thiol could be detected by titration with iodine. The product was easily recrystallized from ethanol. Similar results were obtained using ethyl instead of methyl xanthide.
Workup
- additionof methyl xanthide was added in one portion
- customEvaporation of excess pyridine and volatile byproduct
Sources & evidence
- ORD record
- ord-50c2acc6506747469be11af0d279a759
- Source dataset
- uspto-grants-1977_08
- Patent number
- US04039586
Reaction notes
Loading…