Methyl iodide → Hydrazine
Reaction equation
Cl.[CH3:2][CH:3]1[CH2:7][NH:6][C:5]([NH:8][NH2:9])=[N:4]1.CC1CN[C:13](=[S:16])N1.C[I:18]>C(O)C>[IH:18].[CH3:2][CH:3]1[CH2:7][NH:6][C:5]([S:16][CH3:13])=[N:4]1.[NH2:8][NH2:9]Participants
6
Reactant 3
Product 2
Reagents, catalysts & solvents 1
Procedure
The starting material, 4-methyl-2-imidazolin-2-ylhydrazine hydrochloride, is prepared as follows: 4-methylimidazolidin-2-thione and methyl iodide react in refluxing ethanol to give 4-methyl-2-methylthio-2-imidazoline hydroiodide, which upon treatment with hydrazine in boiling ethanol yields 4-methyl-2-imidazolin-2-ylhydrazine hydroiodide. Subsequent treatment with silver chloride in aqueous or ethanol solution then gives the hydrochloride salt melting at 128°-130° C.
Sources & evidence
- ORD record
- ord-aa83b4f6ff5b4025b5a64cfb28aa0e9e
- Source dataset
- uspto-grants-1977_08
- Patent number
- USRE029358
Reaction notes
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