HRID442861

反应详情

EQUATION

反应方程式

HRID 442861 的结构方程式

PROCEDURE

实验过程

Substantially the same procedure as in Example 89 was repeated using Compound 88 (0.95 g, 1.88 mmol) obtained in Example 88 and 2-pyrrolidinylethylchloride hydrochloride (335 mg, 1.97 mmol) to give 0.61 g (yield: 54%) of the title compound.