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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 445439Generated: October 25, 2026

Hydrogen Bromide → 4-(2-Fluoro-4-nitrophenoxy)-7-hydroxy-6-methoxyquinoline

https://huagongshe.com/reaction/445439

Reaction equation

Participants

RoleNameHCIDCharge
ReactantHydrogen BromideHCID 260—
Reactant7-(Benzyloxy)-4-(2-fluoro-4-nitrophenoxy)-6-methoxyquinolineHCID 22935410—
SolventAcetic AcidHCID 176—
SolventDiethyl EtherHCID 3283—
Product4-(2-Fluoro-4-nitrophenoxy)-7-hydroxy-6-methoxyquinolineHCID 136175701120.2%

Reaction Steps

To a round bottom flask equipped with a magnetic stir bar was added 7-benzyloxy-4-(2-fluoro-4-nitro-phenoxy)-6-methoxy-quinoline (2.9 g, 6.9 mmol, 1.0 eq) and 33% HBr in acetic acid (30 ml). The mixture was stirred at room temperature for 3 hours and diluted with ether to give a pale white solid. The solid was filtered, washed with ether and dried to yield 4-(2-Fluoro-4-nitro-phenoxy)-6-methoxy-quinolin-7-ol as a pale white solid (2.74 g, 97.5% yield). 1H NMR (400 MHz, CDCl3): 11.89 (bs, 1H), 8.87 (d, 1H), 8.57 (d, 1H), 8.30 (d, 1H), 7.89 (m, 1H), 7.73 (s, 1H), 7.55 (s, 1H), 4.03 (s, 3H); MS (EI) for C16H11FN2O5: 421 (M+H+).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08476298B2
Source datasetuspto-grants-2013_07
ORD IDord-59da3a6a72424ad593a6fcbafa80a947
Source noteuspto-grants-2013_07