Hydrochloric Acid → 2-(3-Chloro-4-(quinolin-2-ylmethoxy)phenyl)acetic acid

Participants

Reaction Steps

To a solution of ethyl 2-(3-chloro-4-(quinolin-2-ylmethoxy)phenyl)acetate (1.0 g, 0.02 mol) in 1:1 MeOH:THF (20 mL) was added LiOH.H2O (1.76 g, 0.008 mol). The reaction mixture was then stirred at RT for 16 h and then concentrated in vacuo to obtain the crude product. The crude material was diluted with water and adjusted to pH 4 using 1N HCl. The mixture was then filtered and the residue was dried in vacuo to afford 2-(3-chloro-4-(quinolin-2-ylmethoxy)phenyl)acetic acid (800 mg, 86%) as a solid.

Provenance & Evidence