HRID449547

反应详情

EQUATION

反应方程式

REACTANTS

反应物

$结构：COc1cc(F)c(C2=C(/C=C/C3=[N+](CCCCS(=O)(=O)[O-])c4ccc(S(=O)(=O)[O-])cc4C3(C)C)CCC/C2=C\C=C2\N(CCCCS(=O)(=O)[O-])c3ccc(S(=O)(=O)[O-])cc3C2(C)C)c(F)c1.[Na+].[Na+].[Na+]$

HCID86649231

未命名化合物

HCID86649238

未命名化合物

PRODUCTS

生成物

结构：CC1(C)C(/C=C/C2=C(c3c(F)cc(F)c(CCCCC(=O)O)c3F)C(=C/C=C3/N(CCCCS(=O)(=O)[O-])c4ccc(S(=O)(=O)[O-])cc4C3(C)C)/CCC2)=[N+](CCCCS(=O)(=O)[O-])c2ccc(S(=O)(=O)[O-])cc21.[Na+].[Na+].[Na+]

HCID91870400

未命名化合物

PROCEDURE

实验过程

Compound 39 is prepared analogously to compound 17 (Example 17), except with 5-(3-borono-2,4,6-trifluorophenyl)pentanoic acid as a starting material.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-934f8ac83a9445b38ba04a721f2547b9
来源数据集: uspto-grants-2013_07
DOI: 10.6084/m9.figshare.5104873.v1
专利: US08481752B2
来源说明: uspto-grants-2013_07

反应 SMILES

FC1C=C(OC)C=C(F)C=1[C:11]1=[C:12]([CH:42]=[CH:43][C:44]2[C:52]([CH3:54])([CH3:53])[C:51]3[C:46](=[CH:47][CH:48]=[C:49]([S:55]([O-:58])(=[O:57])=[O:56])[CH:50]=3)[N+:45]=2[CH2:59][CH2:60][CH2:61][CH2:62][S:63]([O-:66])(=[O:65])=[O:64])[CH2:13][CH2:14][CH2:15]/[C:16]/1=[CH:17]\[CH:18]=[C:19]1\[N:20]([CH2:34][CH2:35][CH2:36][CH2:37][S:38]([O-:41])(=[O:40])=[O:39])[C:21]2[C:26]([C:27]\1([CH3:29])[CH3:28])=[CH:25][C:24]([S:30]([O-:33])(=[O:32])=[O:31])=[CH:23][CH:22]=2.[Na+:67].[Na+].[Na+].B([C:73]1[C:74]([F:88])=[C:75]([CH2:81][CH2:82][CH2:83][CH2:84][C:85]([OH:87])=[O:86])[C:76]([F:80])=[CH:77][C:78]=1[F:79])(O)O>>[C:85]([CH2:84][CH2:83][CH2:82][CH2:81][C:75]1[C:74]([F:88])=[C:73]([C:11]2=[C:16]([CH:17]=[CH:18][C:19]3[C:27]([CH3:29])([CH3:28])[C:26]4[C:21](=[CH:22][CH:23]=[C:24]([S:30]([O-:33])(=[O:31])=[O:32])[CH:25]=4)[N+:20]=3[CH2:34][CH2:35][CH2:36][CH2:37][S:38]([O-:41])(=[O:40])=[O:39])[CH2:15][CH2:14][CH2:13]/[C:12]/2=[CH:42]\[CH:43]=[C:44]2\[N:45]([CH2:59][CH2:60][CH2:61][CH2:62][S:63]([O-:66])(=[O:65])=[O:64])[C:46]3[C:51]([C:52]\2([CH3:54])[CH3:53])=[CH:50][C:49]([S:55]([O-:58])(=[O:56])=[O:57])=[CH:48][CH:47]=3)[C:78]([F:79])=[CH:77][C:76]=1[F:80])([OH:87])=[O:86].[Na+:67].[Na+:67].[Na+:67]