Tetrabutylammonium Fluoride → HCID 25143686, compound

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Reaction Steps

367 mg (1.41 mmol; 1 molar in THF) of tetrabutylammonium fluoride are added to a solution of 515 mg (0.703 mmol) of the compound from Example 6A in 8 ml of THF. After 3 h at RT, the mixture is diluted with water, saturated aqueous sodium chloride solution and ethyl acetate. The aqueous phase is extracted with ethyl acetate, and the combined organic phases are dried over sodium sulphate. After filtration, the mixture is freed from the solvent and the residue is purified by chromatography on silica gel (dichloromethane/methanol 20:1). This gives 278 mg (78% of theory) of the desired product.

Provenance & Evidence