HRID453951

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID3587356

未命名化合物

结构：OB(O)c1ccccc1-c1nnnn1C(c1ccccc1)(c1ccccc1)c1ccccc1

HCID10342745

2-(1-TRITYL-1H-TETRAZOL-5-YL)PHENYLBORONIC ACID

C26H21BN4O2

结构：CCCCC(=O)N(Cc1ccc(-c2ccccc2-c2nnnn2C(c2ccccc2)(c2ccccc2)c2ccccc2)cc1)[C@H](C(=O)OC)C(C)C

HCID16726602

Methyl N-pentanoyl-N-({2'-[1-(triphenylmethyl)-1H-tetrazol-5-yl][1,1'-biphenyl]-4-yl}methyl)-L-valinate

C44H45N5O3

PRODUCTS

生成物

结构：CCCCC(=O)N(Cc1ccc(-c2ccccc2-c2nn[nH]n2)cc1)[C@H](C(=O)O)C(C)CC(c1ccccc1)(c1ccccc1)c1ccccc1

HCID21051452

未命名化合物

PROCEDURE

实验过程

WO 2007/005967 discloses the condensation of p-Bromobenzylbromide with valine methyl ester to give (S)-methyl-2-(4-bromobenzylamino)-3-methyl butanoate which on reaction with valeryl chloride to give (S)-methyl-2-(4-bromobenzyl)pentanamido)-3-methylbutanoate. (S)-methyl-2-(4-bromobenzyl)pentanamido)-3-methylbutanoate is treated with 2-(1-trityl-1H-tetrazol-5-yl)phenylboronic acid to give (S)-3-methyl-2-{pentanoyl-[2′-(1-trityl-1H-tetrazol-5-yl)biphenyl-4-ylmethyl]amino}butyric acid methyl ester and base hydrolysis to give trityl valsartan. Triltyl valsartan is treated with an acid to give valsartan.

WORKUP

后处理

customto give

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-632a418b51574626bf30def58d43d16d
来源数据集: uspto-grants-2013_07
DOI: 10.6084/m9.figshare.5104873.v1
专利: US08492577B2
来源说明: uspto-grants-2013_07

反应 SMILES

CC(C)CC([O-])=O.[C:8](N1C(C2C=CC=CC=2B(O)O)=NN=N1)([C:21]1[CH:26]=[CH:25][CH:24]=[CH:23][CH:22]=1)([C:15]1[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=1)[C:9]1[CH:14]=[CH:13][CH:12]=[CH:11][CH:10]=1.C[O:42][C:43](=[O:92])[C@@H:44]([N:48]([C:86](=[O:91])[CH2:87][CH2:88][CH2:89][CH3:90])[CH2:49][C:50]1[CH:55]=[CH:54][C:53]([C:56]2[CH:61]=[CH:60][CH:59]=[CH:58][C:57]=2[C:62]2[N:66](C(C3C=CC=CC=3)(C3C=CC=CC=3)C3C=CC=CC=3)[N:65]=[N:64][N:63]=2)=[CH:52][CH:51]=1)[CH:45]([CH3:47])[CH3:46]>>[CH3:90][CH2:89][CH2:88][CH2:87][C:86]([N:48]([C@H:44]([C:43]([OH:42])=[O:92])[CH:45]([CH2:46][C:8]([C:9]1[CH:14]=[CH:13][CH:12]=[CH:11][CH:10]=1)([C:21]1[CH:22]=[CH:23][CH:24]=[CH:25][CH:26]=1)[C:15]1[CH:16]=[CH:17][CH:18]=[CH:19][CH:20]=1)[CH3:47])[CH2:49][C:50]1[CH:51]=[CH:52][C:53]([C:56]2[C:57]([C:62]3[N:66]=[N:65][NH:64][N:63]=3)=[CH:58][CH:59]=[CH:60][CH:61]=2)=[CH:54][CH:55]=1)=[O:91]