Sodium Hydroxide → HCID 17952314, compound

Participants

Reaction Steps

To the compound of Step B (0.53 g., 2.30 mmol) in MeOH (5.1 mL) was added 1.0N NaOH (2.53 mL, 2.53 mmol). After two days, the solution was concentrated to dryness. The resulting residue was diluted with 1.0N HCl and water was loaded onto a strong cation exchange resin. The resin was washed with water, THF/water (1:1) and then water. The product was then eluted from the resin with pyridine/water (1:9). The eluent was concentrated to dryness to afford about 0.43 g (85%) of the final compound. EIS-MS 220 [M+1].

Provenance & Evidence