Sodium Hydroxide → HCID 58822928, compound

HRID 459233Notes

Reaction equation

HRID 459233 reaction equation
C([O:3][C:4](=[O:20])[C@@H:5]([O:18][CH3:19])[CH2:6][C:7]1[CH:12]=[CH:11][C:10]([O:13][CH2:14][CH2:15][CH2:16]Br)=[CH:9][CH:8]=1)C.[O:21]([C:28]1[CH:33]=[CH:32][C:31]([C:34]2[CH:39]=[CH:38][C:37]([OH:40])=[CH:36][CH:35]=2)=[CH:30][CH:29]=1)[C:22]1[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=1.[OH-].[Na+]>>[CH3:19][O:18][C@@H:5]([CH2:6][C:7]1[CH:8]=[CH:9][C:10]([O:13][CH2:14][CH2:15][CH2:16][O:40][C:37]2[CH:38]=[CH:39][C:34]([C:31]3[CH:32]=[CH:33][C:28]([O:21][C:22]4[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=4)=[CH:29][CH:30]=3)=[CH:35][CH:36]=2)=[CH:11][CH:12]=1)[C:4]([OH:3])=[O:20]

Participants

4

Reactant 3

HCID 14798Sodium HydroxideHCID 12008733HCID 12008733, compoundHCID 58822859(2S)-3-[4-(3-Bromopropoxy)-phenyl]-2-methoxy-propionic acid ethyl ester

Product 1

HCID 58822928HCID 58822928, compound

Procedure

(2S)-3-[4-(3-Bromo-propoxy)-phenyl]-2-methoxy-propionic acid ethyl ester from Example 173, Step A was treated with 4′-phenoxy-biphenyl-4-ol from Step A under the Standard Procedure J. The compound thus obtained was allowed to react under Standard hydrolysis procedure C (NaOH) to give the title compound. MS(ES) for C31H30O6 [M+NH4]+: 516, [M+Na]+: 521.

Workup

  1. customThe compound thus obtained

Sources & evidence

ORD record
ord-0b5513f2d9e04358926dc63e1ca3abad
Source dataset
uspto-grants-2007_03
Patent number
US07192982B2

Reaction notes

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