HRID466110

反应详情

EQUATION

反应方程式

HRID 466110 的结构方程式

PROCEDURE

实验过程

The general procedure of Example 3 was followed using 2.00 g of 5-chloro-4-hydroxy-2-pyridone and 2.75 g of hexanoyl chloride, thereby producing 1.33 g of the title compound in a yield of 40%.