HRID466111

反应详情

EQUATION

反应方程式

HRID 466111 的结构方程式

PROCEDURE

实验过程

The general procedure of Example 5 was followed using 2.00 g of 5-chloro-4-hydroxy-2-pyridone and 2.75 g of hexanoyl chloride to produce 1.22 g of the title compound in a yield of 26%.