Nitric Acid → 3-Nitrophthalic acid
Reaction equation
[N+:1]([O-:4])(O)=[O:2].[C:5]([OH:16])(=[O:15])[C:6]1[C:7](=[CH:11][CH:12]=[CH:13][CH:14]=1)[C:8]([OH:10])=[O:9]>>[N+:1]([C:14]1[CH:13]=[CH:12][CH:11]=[C:7]([C:8]([OH:10])=[O:9])[C:6]=1[C:5]([OH:16])=[O:15])([O-:4])=[O:2]Participants
3
Reactant 2
Product 1
Procedure
100 parts by weight and 150 parts by weight 99% by weight concentrated nitric acid are each added to a reaction vessel and brought to a temperature of 70° C. To each solution is added 10 parts by weight phthalic acid. Nitration is allowed to continue at 70° C. for three hours and produces yields of greater than 90% of theoretical yield consisting essentially of a mixture of 3- and 4- nitrophthalic acid. Table 1 shows the make-up of the reaction product mix in mole percent. The mole ratio of 4- to 3- nitrophthalic acid formed was approximately 1.1:1.
Workup
- additioneach added to a reaction vessel
- custombrought to a temperature of 70° C
- customproduces
- customyields of greater than 90%
- customof theoretical yield
- additionmix in mole percent
Sources & evidence
- ORD record
- ord-920c634ef74d49109dbf00fb319e43d0
- Source dataset
- uspto-grants-1992_10
- Patent number
- US05155234
Reaction notes
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