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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 466464Generated: October 29, 2026

p-Fluoronitrobenzene → 2-n-Butyl-4-chloro-1-(4-nitrophenyl)imidazole-5-carboxaldehyde

https://huagongshe.com/reaction/466464

Reaction equation

Participants

RoleNameHCIDCharge
Reactantp-FluoronitrobenzeneHCID 9590—
ReactantSodium MethoxideHCID 10942334—
ReactantHCID 178418251HCID 178418251—
SolventMethanolHCID 887—
Product2-n-Butyl-4-chloro-1-(4-nitrophenyl)imidazole-5-carboxaldehydeHCID 5453496430%

Reaction Conditions

Temperature100 °C

Reaction Steps

2-n-Butyl-4-chloroimidazole-5-carboxaldehyde (10.00 g, 53.6 mmol, 1 eq.) was dissolved in a freshly prepared solution of sodium methoxide (1.23 g Na, 53.6 mmol, 1 eq.) in methanol (175 mL). The methanol was removed in vacuo and replaced with DMF (100 mL). 4-Fluoro-1-nitrobenzene (11.37 mL, 107.0 mmol, 2 eq.) was then added. The mixture was heated at 100° C. for 36 h. Two more equivalents of 4-fluoro-1-nitrobenzene were then added and the mixture heated at 100° C. for an additional 48 hours. The DMF was removed in vacuo and the residue partitioned between ethyl acetate and water. The aqueous phase was extracted twice more with ethyl acetate, the organic layers combined, dried (MgSO4) and the solvent removed in vacuo. Flash chromatography of the residue over silica gel in 9:1 toluene/ethyl acetate yielded 4.92 g (30%) of an amber oil. NMR (CDCl3): δ 9.74 (s, 1H); 8.42 (d, 2H, J=9 Hz); 7.46 (d, 2H, J=9 Hz); 2.51 (t, 2H, J=7 Hz); 1.67 (t of t, 2H, J=7,7 Hz); 1.30 (t of q, 2H, J=7,7 Hz); 0.84 (t, 3H, J=7 Hz). Anal. calcd. for C14H14ClN3O3 : C, 54.64; H, 4.59; Cl, 11.52, N, 13.65. Found: C, 54.91; H, 4.67; Cl, 11.20; N, 13.62.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05155118
Source datasetuspto-grants-1992_10
ORD IDord-44fcdc029240490e8f5c1309ee9ba8bf
Source noteuspto-grants-1992_10