HRID473572

反应详情

EQUATION

反应方程式

HRID 473572 的结构方程式

PROCEDURE

实验过程

Compound 7c was prepared by the same procedure as described for the preparation of 7a using 6c (99 mg, 0.20 mmol): yield 57 mg (42%), MS: m/z 416 (M+H)+; 1HNMR (D2O) δ 8.37 (s, 1H, H-2), 7.73-7.76 (m, 2H, 8-phenyl o-H's), 7.60-7.70 (m, 3H, 8-phenyl m- and p-H's), 6.02 (d, 1H, H-1′, J1′,2′=5.7 Hz), 5.25 (t, 1H, H-2′, J2′,3′=4.9 Hz), 4.46-4.54 (bm, 2H, H-3′, 4′), 4.03 (t, 2H, NH2O—CH2), 3.87-4.0 (m, 1H, 5′-CH2), 3.61-3.67 (m, 1H, 5′-CH2), 3.50-3.55 (m, 2H, N(CH3)—CH2), 3.0 (s, 3H, N—CH3); UV λmax, nm, pH 1, 275 (∈ 21,600), pH 7, 275 (∈ 17,100), pH 13, 274.4 (∈ 16,800). Anal. (C19H25N7O4.2.0H2SO4.3H2O) C, H, N, S.