HRID478942

反应详情

EQUATION

反应方程式

HRID 478942 的结构方程式

REACTANTS

反应物

2

结构：c1cc[nH+]cc1

Pyridinium

C5H6N+

结构：F[P-](F)(F)(F)(F)F.[Na+]

Sodium hexafluorophosphate

F6NaP

PRODUCTS

生成物

1

结构：F[P-](F)(F)(F)(F)F.c1cc[nH+]cc1

Pyridium hexafluorophosphate

C5H6F6NP

PROCEDURE

实验过程

Pyridinium tetrafluoborate is ion-exchanged with sodium hexafluorophosphate to give pyridinium hexafluorophosphate.