HRID479065

反应详情

EQUATION

反应方程式

HRID 479065 的结构方程式

PROCEDURE

实验过程

A procedure similar to that used to prepare compound 155 was used except that (S)-4-methylnonanoic acid 163 (5.56 g, 32.27 mmol) was used as a reactant to give 164 as an oil (10.70 g 100%). 1H NMR (400 MHz, CDCl3) δ7.42-7.34 (m, 3H), 7.28 (d, J=6.59 Hz, 2H), 5.64 (d, J=7.33 Hz, 1H), 4.74 (quin, J=6.78 Hz, 1H), 2.94-2.85 (m, 2H), 1.73-1.67 (m, 1H), 1.47-1.43 (m, 1H), 1.39-1.22 (m, 7H), 0.90-0.84 (m, 8H).