反应详情

By the method of Example 1, Step G, 11.27 g (0.054 mole) of methyl (2-formyl-5-methylphenoxy)acetate was reacted with 0.54 g (0.014 mole) of sodium borohydride and 0.10 g (0.0018 mole) of sodium methoxide in 30 mL of methanol, yielding 9.41 g of methyl (2-hydroxymethyl-5-methylphenoxy)-acetate as a yellow oil. The NMR spectrum was consistent with the proposed structure.