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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 485142Generated: October 26, 2026

Methyl iodide → 2-(4-Methoxyphenyl)propanenitrile

https://huagongshe.com/reaction/485142

Reaction equation

Participants

RoleNameHCIDCharge
ReactantMethyl iodideHCID 6328—
ReactantAmmonium ChlorideHCID 25517—
ReactantBenzeneacetonitrile, 4-methoxy-HCID 66031—
ReactantButyllithiumHCID 178418339—
SolventTetrahydrofuranHCID 8028—
Product2-(4-Methoxyphenyl)propanenitrileHCID 1229767093.1%

Reaction Conditions

Temperature-78 °C

Reaction Steps

14.7 g (0.10 mole) of p-methoxyphenylacetonitrile was dissolved in 250 ml of dry tetrahyrofuran and placed in a dry ice/isopropanol bath under N2. 69.0 ml of 1.6M n-butyl lithium (0.11 mole) was added dropwise over 30 minutes and the mixture stirred at -78° C. for one hour. The lithium salt of the nitrile precipitated as a yellow solid during this time. 71.0 g (0.50 mole) of methyl iodide was then added and stirring at -78° C. continued for an additional hour. The mixture was then poured into saturated ammonium chloride and the product extracted into diethyl ether, washed with saturated sodium chloride and dried over sodium sulfide. It was filtered and evaporated, redissolved in methylene chloride and passed through Florisel®. Evaporation gave 15.0 g of α-(p-methoxyphenyl)propionitrile as an orange oil.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04535186
Source datasetuspto-grants-1985_08
ORD IDord-6b01b1ff67b242eeb1220a093aec4308
Source noteuspto-grants-1985_08