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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 486179Generated: October 26, 2026

Formaldehyde → Sodium Hydroxide

https://huagongshe.com/reaction/486179

Reaction equation

Participants

RoleNameHCIDCharge
ReactantFormaldehydeHCID 712—
ReactantPhenolHCID 996—
ReactantSodium metaborateHCID 145326—
ProductSodium HydroxideHCID 1479850%
ProductNaOH phenolHCID 19597145—

Reaction Steps

A reactor equipped as in Examples A and B was charged with phenol and formaldehyde in a formaldehyde to phenol molar ratio (F/P) of about 1.5:1. The formaldehyde was charged as a 50% aqueous solution. About 3% by weight based on the total charge of sodium metaborate was added and sufficient 50% aqueous sodium hydroxide to give a mole ratio (NaOH/phenol) of about 0.054:1. The mixture was heated to about 65° C. and held until the free formaldehyde fell to less than about 1.75%. The mixture was cooled to about 55° C. and distilled under vacuum to a non-volatile solids content of about 65%.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05290843
Source datasetuspto-grants-1994_03
ORD IDord-e12fc928095344ec8ff5b476c3af94ff
Source noteuspto-grants-1994_03