huagongshe.com
HRID486700

反应详情

EQUATION

反应方程式

HRID 486700 的结构方程式

REACTANTS

反应物

2
结构：CC(=O)CC(C)=O
HCID31261

2,4-Pentanedione

C5H8O2

结构：O=Cc1ccc(Cl)c([N+](=O)[O-])c1
HCID85505

4-Chloro-3-nitrobenzaldehyde

C7H4ClNO3

PRODUCTS

生成物

1
结构：CC(=O)C(=Cc1ccc(Cl)c([N+](=O)[O-])c1)C(C)=O
HCID11957792

2,4-Pentanedione, 3-[(4-chloro-3-nitrophenyl)methylene]-

C12H10ClNO4

PROCEDURE

实验过程

The procedure described in Example 1 was repeated by using 1.85 g of 4-chloro-3-nitrobenzaldehyde and 1.5 g of 2,4-pentanedione. Yield 1.32 g, mp 110°-111° C.