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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 489250Generated: October 30, 2026

Chloroacetyl chloride → HCID 60054738, compound

https://huagongshe.com/reaction/489250

Reaction equation

Participants

RoleNameHCIDCharge
ReactantChloroacetyl chlorideHCID 6577—
ReactantBenzylamineHCID 7504—
ReactantDiisopropylethylamineHCID 81531—
Reactant4-[(5S,9R)-3-(3,5-Dichlorophenyl)-1-methyl-2,4-dioxo-1,3,7-triazaspiro[4.4]non-9-yl]-benzonitrileHCID 11994754—
Catalyst4-(Dimethylamino)pyridineHCID 14284—
SolventTetrahydrofuranHCID 8028—
ProductHCID 60054738HCID 6005473816.6%

Reaction Steps

To a solution of Example 15 (41.5 mg, 0.1 mmol) in 1 ml THF, were added TEA (0.0194 ml, 0.14 mmol) and chloroacetyl chloride (0.0095 ml, 0.12 mmol). After 15 min. at RT, the reaction mixture was evaporated to dryness to yield 47.8 mg of crude intermediate. To this intermediate (37.7 mg, 0.077 mmol) in 1 ml THF, were added PS-DIEA (Argonaut, 21 mg, 0.06 mmol), benzylamine (4.9 μl, 0.045 mmol) and PS-DMAP (Argonaut, 20 mg, 0.06 mmol). The reaction mixture was stirred for 24 h at RT before evaporation to dryness. The residue was purified by reverse phase HPLC (gradient from CH3CN/H2O/TFA: 5/95/0.05 to CH3CN/H2O/TFA: 80/20/0.05) to yield the titled compound (4.2 mg). Retention time: 10.65 min., 563 (M+1); (LCMS conditions: HP 1100 MSD platform (APCI−, DAD (210-400 nm)), Column: TSK gel Super ODS 4.6 mm ID×10 cm, Flow rate: 1 mL/min, Gradient: from 5% to 95% eluent B in 15 min., with a plateau with 95% eluent B during 5 min. Eluent A: H2O (0.1% ammonium formate), Eluent B: CH3CN). 1H NMR (CDCl3): 7.75-7.6 (2H, d), 7.6-7.15 (8H, m), 7.75 (2H, d), 4.25 (2H, s), 4.2-3.6 (7H,m), 3.3-3.05 (3H, m).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06977267B2
Source datasetuspto-grants-2005_12
ORD IDord-efa4f451874d4e5195d57536ce5e83f8
Source noteuspto-grants-2005_12