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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 48958Generated: October 25, 2026

Potassium Hydroxide → 22,29-EPOXY-3,29-DIHYDROXY-14beta-STIGMASTAN-15-ONE

https://huagongshe.com/reaction/48958

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPotassium HydroxideHCID 14797—
Reactant22,29-Epoxy-3,29-dihydroxy-14alpha-stigmastan-15-oneHCID 53902136—
SolventMethanolHCID 887—
Product22,29-EPOXY-3,29-DIHYDROXY-14beta-STIGMASTAN-15-ONEHCID 69625815—

Reaction Steps

Epimerization of compound 248 at the C14 position using KOH in MeOH yields 22,29-epoxy-3,29-dihydroxy-14β-stigmastan-15-one (260). Compound 248 is dissolved in MeOH and a solution of KOH in MeOH (25 mg/ml) is added. The mixture is refluxed for 15 minutes then cooled to room temperature. Water is added and the aqueous slurry is extracted with chloroform and then dried over MgSO4. Filtration and concentration gives the crude product that contains an epimeric mixture of compounds 248 and 260. Separation of 248 and 260 is achieved using column chromatography.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06706701B1
Source datasetuspto-grants-2004_03
ORD IDord-fb8b473e4cc04ca99f6ff93f6ada0203
Source noteuspto-grants-2004_03