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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 491497Generated: October 30, 2026

Ammonium Chloride → HCID 57678400, compound

https://huagongshe.com/reaction/491497

Reaction equation

Participants

RoleNameHCIDCharge
ReactantAmmonium ChlorideHCID 25517—
ReactantTrimethylsilylacetyleneHCID 66111—
ReactantDiisopropylethylamineHCID 81531—
ReactantHCID 57678441HCID 57678441—
CatalystCopper(1+) iodide; Copper(I) iodide; Cuprous iodide; Cuprous iodide (CuI)HCID 24350—
CatalystHCID 178418476HCID 178418476—
SolventTetrahydrofuranHCID 8028—
ProductHCID 57678400HCID 57678400—

Reaction Conditions

Temperature50 °C

Reaction Steps

5-(2,5-Diiodo-4-methoxy-phenoxy)-pyrimidine-2,4-diamine (1.2 g, 2.5 mmol), bis(triphenylphosphine)palladium dichloride (175 mg, 2.5 mmol), and CuI (25 mg, 0.125 mmol) were added to 7 mL dry THF. Trimethylsilylacetylene ((0.48 mL, 3.3 mmol), and diisopropylethylamine (3.5 mL) were added, and the reaction mixture was heated to 50° C. under nitrogen for 27 hours. The reaction mixture was cooled, poured into 15% aqueous NH4Cl and extracted into EtOAc. The combined organic layers were washed with brine, dried over MgSO4, filtered and concentrated under reduced pressure to give crude 5-(4-Methoxy-2,5-bis-trimethylsilanylethynyl-phenoxy)-pyrimidine -2,4-diamine together with monoacetylenes 5-(2-iodo-4-methoxy-5-trimethylsilanylethynyl-phenoxy)-pyrimidine-2,4-diamine and 5-(5-iodo-4-methoxy-2-trimethylsilanylethynyl-phenoxy)-pyrimidine-2,4-diamine. This residue was chromatographed on 125 g of flash silica (6:1:1 CH2Cl2:MeOH:NH4OH) to give 450 mg of 5-(4-Methoxy-2,5-bis-trimethylsilanylethynyl-phenoxy)-pyrimidine-2,4-diamine, MS (M+H)=425.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07531547B2
Source datasetuspto-grants-2009_05
ORD IDord-8a52e746ed94424ea108d613d7bcc4d5
Source noteuspto-grants-2009_05