HRID49352

反应详情

EQUATION

反应方程式

HRID 49352 的结构方程式

PROCEDURE

实验过程

In a manner similar to that of Example 6(f), by reaction of 6.7 g (18 mmol) of dimethyl 4-{2-[2-(2-ethyl-[1,3]dioxolan-2-yl)-4-thienyl]ethyl}phthalate with 1.6 g (43 mmol) of lithium aluminium hydride, the desired product is obtained in the form of a colourless oil (m=5.3 g; Y=85%).