HRID494606

反应详情

EQUATION

反应方程式

HRID 494606 的结构方程式

PROCEDURE

实验过程

The title compound was prepared according the procedure of Example 5B, substituting the product of Example 1F for the product of Example 4F. 1H NMR (300 MHz, CDCl3) δ ppm 0.55 (m, 2H) 0.67 (m, 4.8H) 0.79 (m, 1.2H) 0.98 (m, 2H) 1.78 (m, 2H) 2.19 (m, 2H) 3.69 (s, 0.4H) 6.13 (s, 0.8H) 7.41 (m, 2H) 7.56 (m, 0.8H) 7.67 (m, 0.2H) 8.07 (m, 0.2H) 8.13 (m, 0.8H).