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HRID500383

反应详情

EQUATION

反应方程式

HRID 500383 的结构方程式

REACTANTS

反应物

2
结构：COc1ccc(C(=O)Cl)cc1
HCID7477

Benzoyl chloride, 4-methoxy-

C8H7ClO2

结构：CC(C)(C)OC(=O)NC1CCCOCC=CC2CC2(C(=O)NS(=O)(=O)C2CC2)NC(=O)C2CC(O)CN2C1=O
HCID72260122

未命名化合物

PRODUCTS

生成物

1
结构：COc1ccc(C(=O)OC2CC3C(=O)NC4(C(=O)NS(=O)(=O)C5CC5)CC4C=CCOCCCC(NC(=O)OC(C)(C)C)C(=O)N3C2)cc1
HCID86612083

未命名化合物

收率 36%

PROCEDURE

实验过程

Prepared by way of method I using 18-hydroxy-14-tert-butoxycarbonylamino-4-cyclopropylsulfonylaminocarbonyl-2,15-dioxo-3,16-diaza-10-oxatricyclo[14.3.0.04,6]-nonadec-7-ene (100 mg, 0.175 mmol) and 4-methoxybenzoyl chloride (89 mg, 0.53 mmol). The final trituration (diethyl ether) and filtration gave 44 mg (36%) of 18-(4-methoxybenzoyloxy)-14-tert-butoxycarbonylamino-4-cyclopropylsulfonylaminocarbonyl-2,15-dioxo-3,16-diaza-10-oxatricyclo-[14.3.0.04,6]-nonadec-7-ene as a white powder: 98.9% pure (HPLC), MS m/z 703 (M−H)−, HRMS: calcd. 705.2806 and found 705.2801 (M+H)+, mp 145-147° C.

WORKUP

后处理

  1. customPrepared by way of method I
  2. filtrationThe final trituration (diethyl ether) and filtration