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HRID500387

反应详情

EQUATION

反应方程式

HRID 500387 的结构方程式

REACTANTS

反应物

2
结构：O=C(Cl)c1ccc(Oc2ccccc2)cc1
HCID74193

Benzoyl chloride, 4-phenoxy-

C13H9ClO2

结构：CC(C)(C)OC(=O)NC1COCCCC=CC2CC2(C(=O)NS(=O)(=O)C2CC2)NC(=O)C2CC(O)CN2C1=O
HCID72260127

未命名化合物

PRODUCTS

生成物

1
结构：CC(C)(C)OC(=O)NC1COCCCC=CC2CC2(C(=O)NS(=O)(=O)C2CC2)NC(=O)C2CC(OC(=O)c3ccc(Oc4ccccc4)cc3)CN2C1=O
HCID72445379

未命名化合物

收率 12%

PROCEDURE

实验过程

Prepared by way of method I using 18-hydroxy-14-tert-butoxycarbonylamino-4-cyclopropylsulfonylaminocarbonyl-2,15-dioxo-3,16-diaza-12-oxatricyclo[14.3.0.04,6]-nonadec-7-ene (100 mg, 0.175 mmol) and 4-phenoxybenzoyl chloride (111 mg, 0.53 mmol). The final trituration (diethyl ether/hexane) and filtration gave 16 mg (12%) of 18-(4-phenoxybenzoyloxy)-14-tert-butoxycarbonylamino-4-cyclopropylsulfonylaminocarbonyl-2,15-dioxo-3,16-diaza-12-oxatricyclo-[14.3.0.04,6]-nonadec-7-ene as a white powder: 97.5% pure (HPLC), MS m/z 765 (M−H)−, HRMS: calcd. 784.3228 and found 784.3208 (M+NH4)+, mp 207-209° C.

WORKUP

后处理

  1. customPrepared by way of method I
  2. filtrationThe final trituration (diethyl ether/hexane) and filtration