HRID50155

反应详情

EQUATION

反应方程式

HRID 50155 的结构方程式

PROCEDURE

实验过程

The same procedure was used as that in example 3, except that 4-(3-chloro-phenyl)-6-[(5-chloro-pyridin-2-yl)-hydroxy-(3-methyl-3H-imidazol-4-yl)-methyl]-1-cyclopropylmethyl-1H-quinolin-2-one (258 mg, 0.486 mmol was used in the place of 4-(3-chloro-phenyl)-6-[(6-chloro-pyridin-3-yl)-hydroxy-(3-methyl-3H-imidazol-4-yl)-methyl]-1-methyl-1H-quinolin-2-one, to give the title compound as a white solid, 112 mg (0.21 mmol, 43% yield).