1-(4-Fluorophenoxy)-3-nitrobenzene → 3-(4-Fluorophenoxy)aniline

HRID 50502Notes

Reaction equation

HRID 50502 reaction equation
[F:1][C:2]1[CH:17]=[CH:16][C:5]([O:6][C:7]2[CH:8]=[C:9]([N+:13]([O-])=O)[CH:10]=[CH:11][CH:12]=2)=[CH:4][CH:3]=1>C(O)C.[Pd]>[F:1][C:2]1[CH:17]=[CH:16][C:5]([O:6][C:7]2[CH:8]=[C:9]([CH:10]=[CH:11][CH:12]=2)[NH2:13])=[CH:4][CH:3]=1

Participants

4

Procedure

EX-634B) 3-(4Fluorophenoxy)nitrobenzene (1.15 g, 4.93 mmol) from EX-634A was dissolved in ethanol (45 mL), and the solution was hydrogenated for 4 h in the presence of 5% palladium on charcoal. After the mixture was filtered through celite, the ethanol was removed in vacuo. The product was purified by flash column chromatography on silica gel eluting with ethyl acetate in hexane (1:10) to give 0.92 g (90%) of 3-(4-fluorophenoxy)aniline as a yellow oil, 99% pure by HPLC analysis. HRMS calcd. for C12H11FNO: 204.0824 [M+H]+, found: 204.0837.

Workup

  1. filtrationAfter the mixture was filtered through celite
  2. customthe ethanol was removed in vacuo
  3. customThe product was purified by flash column chromatography on silica gel eluting with ethyl acetate in hexane (1:10)

Sources & evidence

ORD record
ord-899a0c6dd93e4de19bcc96b450700d3d
Source dataset
uspto-grants-2004_03
Patent number
US06710089B2

Reaction notes

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