HRID51045

反应详情

EQUATION

反应方程式

HRID 51045 的结构方程式

PROCEDURE

实验过程

The 4-((6bR,10aS)-1,2,6b,9,10,10a-hexahydropyrido[4,3-b][1,4]thiazino[2,3,4-hi]indol-8(7H)-yl)-1-(4-fluorophenyl)-1-butanone (349 mg, 25%) was prepared from (6bR,10aS)-1,2,6b,7,8,9,10,10a-octahydropyrido[4,3-b][1,4]thiazino[2,3,4-hi]indolehydrochloride (750 mg, 2.79 mmol) with 4-chloro-1-(4-fluorophenyl)-1-butanone (3.0 mL, 15.24 mmol) using the procedure described in Example 456 Step A.