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HRID521962

反应详情

EQUATION

反应方程式

HRID 521962 的结构方程式

REACTANTS

反应物

3
结构：CC(C)(C)OC(=O)Nc1sc(-c2cccc(F)c2F)nc1C(=O)O
HCID58182144

未命名化合物

结构：Cn1ncc(NC(=O)c2nc(Br)sc2NC(=O)OC(C)(C)C)c1[C@@H]1CC[C@@H](NC(=O)OC(C)(C)C)[C@@H](F)CO1
HCID86713830

未命名化合物

结构：Cn1ncc([N+](=O)[O-])c1[C@@H]1CC[C@@H](NC(=O)OC(C)(C)C)[C@H](F)CO1
HCID86713841

未命名化合物

PRODUCTS

生成物

1
结构：Cn1ncc(NC(=O)c2nc(-c3cccc(F)c3F)sc2N)c1[C@@H]1CC[C@@H](N)[C@@H](F)CO1
HCID90072511

未命名化合物

PROCEDURE

实验过程

Following the procedure for Example 111 starting from tert-butyl N-[(3S,4R,7S)-3-fluoro-7-(2-methyl-4-nitro-pyrazol-3-yl)oxepan-4-yl]carbamate (Intermediate 88), and replacing 5-((tert-butoxycarbonyl)amino)-2-(2,6-difluorophenyl)thiazole-4-carboxylic acid with 5-(tert-butoxycarbonylamino)-2-(2,3-difluorophenyl)thiazole-4-carboxylic acid (Example 25) gave 181 as the hydrochloride salt as a pale pink solid (30 mg, 38% over three steps). 1H NMR (400 MHz, d6-DMSO) δ 9.42 (s, 1H), 8.54-8.41 (m, 4H), 7.96-7.89 (m, 1H), 7.67 (s, 1H), 7.50-7.39 (m, 3H), 5.28 (m, 1H), 4.84 (d, J=10.4 Hz, 1H), 4.33-4.17 (m, 1H), 4.11-3.99 (m, 1H), 3.78 (s, 3H), 3.74-3.52 (m, 1H), 2.16-1.81 (m, 4H). LCMS (ES+) m/z 467 (M+1).