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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 533572Generated: October 30, 2026

4-(4-Fluorophenyl)phenethyl alcohol → 4-Fluoro-4'-(2-iodoethyl)biphenyl

https://huagongshe.com/reaction/533572

Reaction equation

Participants

RoleNameHCIDCharge
Reactant4-(4-Fluorophenyl)phenethyl alcoholHCID 2759131—
Reactant1-Bromo-4-(2-iodoethyl)benzeneHCID 19702222—
Product4-Fluoro-4'-(2-iodoethyl)biphenylHCID 66577934100%

Reaction Steps

The title compound (650 mg, 100%) was prepared following the general procedure of step 1, Preparation 2, outlined for 1-bromo-4-(2-iodoethyl)benzene except that 2-(4′-fluorobiphenyl-4-yl)ethanol (430 mg, 1.99 mmol) was used in place of 2-(4-bromophenyl)ethanol. 1H NMR (400 MHz, CHLOROFORM-d) δ ppm 3.23 (t, J=7.69 Hz, 2H) 3.39 (t, J=7.69 Hz, 2H) 7.13 (t, J=8.72 Hz, 2H) 7.24-7.30 (m, 2H) 7.48-7.58 (m, 4H).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08853258B2
Source datasetuspto-grants-2014_10
ORD IDord-dc7e09062afc469f97b5ee4be8dc0a5a
Source noteuspto-grants-2014_10