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HRID536548

反应详情

EQUATION

反应方程式

HRID 536548 的结构方程式

REACTANTS

反应物

2
结构：COC(=O)c1cccc(Cn2nc(-c3ccc(Cl)cc3)n(CC(O)C(F)(F)F)c2=O)c1
HCID58460127

未命名化合物

结构：O=C(O)c1ccc(Cn2nc(-c3ccc(Cl)cc3)n(CC(O)C(F)(F)F)c2=O)cc1
HCID58460137

未命名化合物

PRODUCTS

生成物

1
结构：O=C(O)c1cccc(Cn2nc(-c3ccc(Cl)cc3)n(CC(O)C(F)(F)F)c2=O)c1
HCID58460130

未命名化合物

PROCEDURE

实验过程

In the same way as for the compound from Example 28A, 265 mg (0.58 mmol) of the compound from Example 25A were reacted. This gave 250 mg (97% of theory) of the target compound.