HRID538936

反应详情

EQUATION

反应方程式

HRID 538936 的结构方程式

REACTANTS

反应物

2

结构：O=C1CSC(=O)N1

Thiazolidinedione

C3H3NO2S

结构：CCCCCCCCCCCCCCCCCC=O

Octadecanal

C18H36O

PRODUCTS

生成物

1

$结构：CCCCCCCCCCCCCCCCC/C=C1\SC(=O)NC1=O$

未命名化合物

PROCEDURE

实验过程

TZD18 was prepared according to General Procedure A presented hereinabove using 2,4-thiazolidinedione and stearaldehyde as reactants.