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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 539437Generated: October 30, 2026

2,2,3,3-Tetrafluoro-1-propanol → 1,1,1,2,3,3-Hexafluoro-3-(2,2,3,3-tetrafluoropropoxy)propane

https://huagongshe.com/reaction/539437

Reaction equation

Participants

RoleNameHCIDCharge
Reactant2,2,3,3-Tetrafluoro-1-propanolHCID 6441—
ReactantHexafluoropropyleneHCID 8302—
ReactantPotassium HydroxideHCID 14797—
ReactantFluorineHCID 24524—
SolventWaterHCID 962—
SolventDiethyl EtherHCID 3283—
Product1,1,1,2,3,3-Hexafluoro-3-(2,2,3,3-tetrafluoropropoxy)propaneHCID 278228580%

Reaction Steps

Into a 3-liter autoclave were poured 84 g (1.35 mol) of KOH, 800 ml of H2O and 600 g (4.5 mol) of 2,2,3,3-tetrafluoropropanol: CHF2CF2CH2OH. Then, 681 g (4.5 mol) of hexafluoropropene: CF2═CFCF3 was introduced thereto. After completion of the reaction, the reaction solution was separated into two layers, and the lower layer was washed with water three times to separate the solution. After that, refining by distillation was carried out, and 1,015 g (3.6 mol) of a fluorine-containing chain ether (B1a): CHF2CF2CH2OCF2CHFCF3 was obtained (yield 80%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08871384B2
Source datasetuspto-grants-2014_10
ORD IDord-74b52a9f326d4f5da2bc9885c1ac9ad5
Source noteuspto-grants-2014_10