HRID539555

反应详情

EQUATION

反应方程式

HRID 539555 的结构方程式

PROCEDURE

实验过程

Reaction of 159e (0.18 g, 0.532 mmol) and P4S10 (0.118 g, 0.266 mmol) under neat conditions as described for synthesis of 162b gave compound 162e (0.080 g, 42%) as a olive green semi-solid. 1H NMR (400 MHz, CDCl3) δ 8.57 (s, 1H), 7.83 (d, J=7.5 Hz, 2H), 7.76 (s, 1H), 7.41 (t, J=7.5 Hz, 2H), 7.32 (m, 2H), 6.94 (m, 1H), 6.72 (m, 1H), 4.49 (m, 2H), 4.40 (t, J=6.9 Hz, 2H), 1.97 (m, 4H), 1.36 (m, 4H). 13C NMR (100 MHz, CDCl3) δ 164.38, 162.90, 147.70, 130.54, 128.76, 128.03, 126.64, 125.61, 119.51, 118.75, 118.29, 59.74, 50.10, 29.91, 27.99, 25.82, 25.65. HRMS (ESI) calcd for C19H23N4OS [M+H]+ 355.158. found 355.1632.