HRID541765

反应详情

EQUATION

反应方程式

HRID 541765 的结构方程式

PROCEDURE

实验过程

The desired compound was prepared according to the procedure of Example B26, using 6-chloro-2,4,8,22-tetraazatetracyclo[14.3.1.1(3,7).1(9,13)]docosa-1(20),3(22),4,6,9(21),10,12,16,18-nonaen-12-amine dihydrochloride and cyclobutanecarboxylic acid chloride as the starting materials in 40% yield. LCMS for C23H23ClN5O (M+H)+: m/z=420.3.