HRID542014

反应详情

EQUATION

反应方程式

HRID 542014 的结构方程式

PROCEDURE

实验过程

The desired compound was prepared according to the procedure of Example D41 using 6-chloro-12-(2-piperidin-4-ylethoxy)-2,4,8,18,22-pentaazatetracyclo[14.3.1.1(3,7).1(9,13)]docosa-1(20),3(22),4,6,9(21),10,12,16,18-nonaene tris(trifluoroacetate) and 1-fluoro-3-isocyanatobenzene as the starting materials in 60% yield. LCMS for C31H32ClFN7O2 (M+H)+: m/z=588.1.