HRID55041

反应详情

EQUATION

反应方程式

HRID 55041 的结构方程式

PROCEDURE

实验过程

The procedure similar to that described in Example 1 was repeated, except that 478.0 mg (1.00 mol) of Compound 24 was used and N-(2-bromoethyl)phthalimide was used in place of methyl iodide. As a result, 200 mg (yield: 31%) of Compound 33 was obtained as pale yellow crystals.