N-3-Bromopropylphthalimide → HCID 19033975, compound

HRID 55042Notes

Reaction equation

HRID 55042 reaction equation
[CH3:1][O:2][C:3]1[CH:4]=[C:5]2[C:10](=[CH:11][C:12]=1[O:13][CH3:14])[N:9]=[CH:8][N:7]=[C:6]2[N:15]1[CH2:20][CH2:19][CH:18]([N:21]2[C:30](=[O:31])[C:29]3[C:24](=[CH:25][CH:26]=[C:27]([N+:32]([O-:34])=[O:33])[CH:28]=3)[NH:23][C:22]2=[O:35])[CH2:17][CH2:16]1.Br[CH2:37][CH2:38][CH2:39][N:40]1[C:44](=[O:45])[C:43]2=[CH:46][CH:47]=[CH:48][CH:49]=[C:42]2[C:41]1=[O:50]>>[CH3:1][O:2][C:3]1[CH:4]=[C:5]2[C:10](=[CH:11][C:12]=1[O:13][CH3:14])[N:9]=[CH:8][N:7]=[C:6]2[N:15]1[CH2:20][CH2:19][CH:18]([N:21]2[C:30](=[O:31])[C:29]3[C:24](=[CH:25][CH:26]=[C:27]([N+:32]([O-:34])=[O:33])[CH:28]=3)[N:23]([CH2:37][CH2:38][CH2:39][N:40]3[C:44](=[O:45])[C:43]4=[CH:46][CH:47]=[CH:48][CH:49]=[C:42]4[C:41]3=[O:50])[C:22]2=[O:35])[CH2:17][CH2:16]1

Participants

3

Procedure

The procedure similar to that described in Example 1 was repeated, except that 478.0 mg (1.00 mol) of Compound 24 was used and N-(3-bromopropyl)phthalimide was used in place of methyl iodide. As a result, 280 mg (yield: 42%) of Compound 34 was obtained as a pale yellow amorphous solid.

Sources & evidence

ORD record
ord-08f71c1e331043718c2d72c38ff073f0
Source dataset
uspto-grants-1997_04
Patent number
US05624926

Reaction notes

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